Author Topic: Disclaimer: a=a, a=1.  (Read 69 times)

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Offline Chris Dowdle

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Disclaimer: a=a, a=1.
« on: October 16, 2018, 09:28:37 am »
The terms: Applied Theatrics and Story Math/(Fantasy Math), are complete fabrications. Fictitious: where a=you and b=fictitious and where a+b=c=g, g=(a+b) (c=c3=g)

Applied Theatrics: where a=applied theatrics, and b=a=b2=you+others: a+b2=c=t, t=a+b2=c5=t)

Story Math: where a=story math, and b=a and a=you and where b=b2=everything else. (c=c=z) z=(a2+b2) or 2+2=4=c=c4=z)

(Fantasy Math): a=you and b=(Fantasy Math)=c=c+d=t or c=c5

The telling of this story, therefore has two subsets where a=g and b=z and a+b=c or g+z=c=h=(a+b+b2) (c=c4=h)

And for effect: I shall introduce 'c3' as in c=ci3 where i=infinity3, and where ci3=c=(a+b+c)=ci3, and ci3=y (ci3=c3=y).

The formula: h-z=c, means what? The telling of a story, without Story Math. where z=story math, ergo: z-h=c=0=c (4-4=0) and where...
(f+g)+(z-h))=c... and adding c to c gives you different sums, cuz the equations are different... and yet c+c+c+c=c. or as assigned:
c=f+c=g=t-c=z-c=h=c-3. (c=c-3=p=-3=p), Looky see... t-p=f or c=c2. f+?=?, what if, if?... iffy things are negative, like p, p=-3 or p=p3, if, if it gets out of hand... -p3+-p3=c-6 or-2p3... keeping it on the down-low... don't want negatives, above zero, so they stay below the zero-line, where negative numbers belong. (reverse/inverse=abstract=charts-plotted)

f+g=7 and where z+h=8 and so 7+8=15 or c=c15 and where c13=w and w-z=10 and 10/y=3.333, which falls short of that target where:c=c=c5. So if c=c5 is the goal, then 3.333 falls short by: a=3.333 and b=5, ergo b-a=1.667. (c=c+c+c+c/y=c~=k) where (t=target=c=c5=t)

And so if c=c3.333 then if f+g+z+h=c5 then 2+3+4+4=13/y=4.333 or +/-c=c5 or c=t-c=. As it stands:

-f+-z+h+g=c c=-3+-4+4+4=1 or c=c1. (c=c1=s) (all of this is subject to change when a not equal you and is assigned something else: a=food and b=belly where current: b-a2=c or c=s.

s=c1, f=c2, y=c3~g=c3, z=c4, k=c~, h=c4, and t=c5

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